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1. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was?
Sol:
Number of valid votes = 80% of 7500
= (80/100×7500)
= (0.8×7500)
= 6000.
Valid votes polled by other candidates = 45% of 6000
= (45/100×6000)
= (0.45×6000)
= 2700.
2. Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%. then what was the cost of the tax free items ?
Sol: Let the amount of taxable purchases be Rs.x.
Then, 6% of x = 30/100
6/100 × x = 30/100
x = (30/100×100/6)
= 5.
Cost of tax free items = Rs.[25 - (5 + 0.30)]
= Rs. 19.70
3. A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?
Sol: Actual price = Rs. (25 + 2.50)
= Rs. 27.50
Therefore, saving = (2.50 / 27.50 ×100)%
= 100 / 11%
= 9×1/11%
= 9%.
4. What percent of a day is 3 hours?
Sol: Required percentage = (3/24×100)%
= (25 / 2)%.
= 12×1/2%.
5. How many litres of pure acid are there in 8 litres of a 20% solution?
Sol: Quantity of pure acid = 20% of 8 litres
= (20/100×8)litres
= 1.6 litres.
Sol:
Number of valid votes = 80% of 7500
= (80/100×7500)
= (0.8×7500)
= 6000.
Valid votes polled by other candidates = 45% of 6000
= (45/100×6000)
= (0.45×6000)
= 2700.
2. Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%. then what was the cost of the tax free items ?
Sol: Let the amount of taxable purchases be Rs.x.
Then, 6% of x = 30/100
6/100 × x = 30/100
x = (30/100×100/6)
= 5.
Cost of tax free items = Rs.[25 - (5 + 0.30)]
= Rs. 19.70
3. A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?
Sol: Actual price = Rs. (25 + 2.50)
= Rs. 27.50
Therefore, saving = (2.50 / 27.50 ×100)%
= 100 / 11%
= 9×1/11%
= 9%.
4. What percent of a day is 3 hours?
Sol: Required percentage = (3/24×100)%
= (25 / 2)%.
= 12×1/2%.
5. How many litres of pure acid are there in 8 litres of a 20% solution?
Sol: Quantity of pure acid = 20% of 8 litres
= (20/100×8)litres
= 1.6 litres.
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